Legs 6 cm and 8 cm
- a² + b² = c² gives 36 + 64 = c².
- c² = 100 cm², so c = 10 cm.
- The lengths are 6, 8 and 10; the square areas are 36, 64 and 100.
See why the squares belong in the theorem.
Explain why the squares on the legs have the same total area as the square on the hypotenuse.
In a right triangle, the two sides meeting at the right angle are the legs. The side opposite the right angle is the hypotenuse; it is the longest side. Rotating the triangle does not change these roles. The hypotenuse is not automatically the horizontal, vertical or bottom side.
Predict first. Change one value, then explain the result. Diagrams show the entered dimensions; displayed decimals are rounded.
For legs a and b and hypotenuse c, a² + b² = c². A square constructed on each leg has area a² or b²; together those areas equal the area of the square on the hypotenuse. The statement adds square areas, not side lengths. It applies to right triangles, not every triangle.
For legs 3 and 4, the smaller square areas are 9 and 16. Their sum is 25, giving hypotenuse √25 = 5. Changing a leg changes both its square area and the resulting hypotenuse. The attached-square diagram uses actual geometry; the written labels state which side each area belongs to.
Math AnticsPause before the calculation. Identify the legs, hypotenuse and three square areas.
Open on YouTube →A right triangle has legs 5 and 12. What are the three square areas?
The hypotenuse-square area is the sum of the two leg-square areas.
25 and 144 are the smaller areas. Their sum is 169, so the hypotenuse is 13.
Work through eight questions. Two independent correct answers introduce a harder version; supported answers bring the next question back to the foundation. You can use hints at any time.
This round saves on this device. It is practice, not a school mark.
If every side of a right triangle doubles, explain why every attached square has four times the area while the theorem remains true.
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